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What am I doing wrong here?

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Old Mar 17, 2009 | 03:00 PM
  #41  
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Originally Posted by cpvdh
oh holy fuck dont do it that way

y=ln(x^4 + 5x^2)^(3/2)
use ln manip. to get
y=(3/2)(ln(x^4 + 5x^2)

then use the def of deriv of ln to get
y'=(3/2) [(1/(x^4 + 5x^2))(4x^3 + 10x)]

simplify
y'=(12x^3 + 30x)/(2x^4 + 10x^2)


basically y=ln(x)
y'=(dx/x)
but only for lower level stuff, dont do this in 253 or above
ok good call!

Last edited by Red X; Mar 17, 2009 at 03:15 PM.
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Old Mar 17, 2009 | 03:06 PM
  #42  
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the answer in the back of the book is

3(2x^2+5)/[x(x^2+5)]
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Old Mar 17, 2009 | 03:07 PM
  #43  
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Originally Posted by F22B Prelude
the answer in the back of the book is

3(2x^2+5)/[x(x^2+5)]
Yeah, thats my denominator

Check the numerator and see if it reduces. But cpvdh's method is quicker

Last edited by Red X; Mar 17, 2009 at 03:15 PM.
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Old Mar 17, 2009 | 03:10 PM
  #44  
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Originally Posted by F22B Prelude
the answer in the back of the book is

3(2x^2+5)/[x(x^2+5)]
y'=(12x^3 + 30x)/(2x^4 + 10x^2)
y'=6x(2x^2 + 5) / 2x^2(x^2 +5)
y'=3(2x^2 +5)/(x(x^2 +5)
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Old Mar 17, 2009 | 03:11 PM
  #45  
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there was a typo:

corrected:

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Old Mar 17, 2009 | 03:12 PM
  #46  
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So far the only thing I can grab from this is

(1/x)(x')

But what about the 3/2 power?
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Old Mar 17, 2009 | 03:12 PM
  #47  
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Originally Posted by cpvdh
y'=(12x^3 + 30x)/(2x^4 + 10x^2)
y'=6x(2x^2 + 5) / 2x^2(x^2 +5)
y'=3(2x^2 +5)/(x(x^2 +5)
I like it.

Last edited by Red X; Mar 17, 2009 at 03:18 PM.
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Old Mar 17, 2009 | 03:16 PM
  #48  
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dammit learn your log rules!!!!

anything of the form ln(sdhjfgksdfg)^A can be written as A(ln(sdkfhsdkfghsdfg))
just move the exponent out as a scaler, super useful
look at my first link, there are a few rules you really need to know to do the algebra manipulation to get these types of problems into the proper form for them to be super easy
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Old Mar 17, 2009 | 03:31 PM
  #49  
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For completeness:

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Old Mar 17, 2009 | 03:47 PM
  #50  
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Originally Posted by Red X
For completeness:

bah, nooooooooo
you cant break the ln(a + b) into ln(a) + ln (b) that is not correct!!!!

you are thinking of ln(ab)=ln(a) + ln(b)
multiplication changes to addition, division changes to subtraction

http://www.mathwords.com/l/logarithm_rules.htm
for all rules

wait, thats not even quite what you are doing
whatever it is, line 2 is not correct from line 1
you cant split the ln(a+b) into anything else its in its basic form

Last edited by cpvdh; Mar 17, 2009 at 03:50 PM.
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