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Old Mar 17, 2009 | 03:10 PM
  #44  
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cpvdh
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Originally Posted by F22B Prelude
the answer in the back of the book is

3(2x^2+5)/[x(x^2+5)]
y'=(12x^3 + 30x)/(2x^4 + 10x^2)
y'=6x(2x^2 + 5) / 2x^2(x^2 +5)
y'=3(2x^2 +5)/(x(x^2 +5)
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