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What am I doing wrong here?

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Old Mar 17, 2009 | 03:53 PM
  #51  
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Red X
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From: Upstate
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Originally Posted by cpvdh
bah, nooooooooo
you cant break the ln(a + b) into ln(a) + ln (b) that is not correct!!!!

you are thinking of ln(ab)=ln(a) + ln(b)
multiplication changes to addition, division changes to subtraction

http://www.mathwords.com/l/logarithm_rules.htm
for all rules

wait, thats not even quite what you are doing
whatever it is, line 2 is not correct from line 1
you cant split the ln(a+b) into anything else its in its basic form
what?

Sure, you can factor out the x^2!

I did this ( ln(x^2(x^2+5) ). The answer is fine the way it is.

Last edited by Red X; Mar 17, 2009 at 03:56 PM.
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Old Mar 17, 2009 | 04:01 PM
  #52  
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Originally Posted by Red X
what?

Sure, you can factor out the x^2!

I did this ( ln(x^2(x^2+5) ). The answer is fine the way it is.
haha, i see now
i thought you split the ln into two parts from the addition, not through the mult.
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Old Mar 17, 2009 | 04:02 PM
  #53  
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Originally Posted by cpvdh
haha, i see now
i thought you split the ln into two parts from the addition, not through the mult.

That would be a noob mistake, like the chain rule derivation I made earlier . Its been 6 years since I have done non-specific derivatives I like being refreshed. I spend too much time involved on specific problems ftl.

Last edited by Red X; Mar 17, 2009 at 04:04 PM.
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Old Mar 17, 2009 | 04:11 PM
  #54  
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cpvdh
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Originally Posted by Red X
That would be a noob mistake, like the chain rule derivation I made earlier . Its been 6 years since I have done non-specific derivatives I like being refreshed. I spend too much time involved on specific problems ftl.

yeah, i havent touched this stuff in quite a while, calc was in like 2001 i think
and after that it was mostly theory, didnt touch a derivative until i worked at a comm.col. and then it was the rarity since they only offered the first calc class

i cant even understand my gf when she talks about her grad school crap :thinking:

i miss math, good times
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