This should close the case.

 

:rofl:



Bwahaha.

 

repeating decimals are not approximations in any way, they are exact

here is my mth491 book

numbers: rational and irrational
by: ivan niven

pay attention to problem set 8, number 1, part f

the last pic is the solutions in the back of the book

problem set 8, number 1, part f

from this i conclude that writing .999 repeating as a fraction is exactly 1
thus .999... = 1

 

No it won't because Asian's still stand by the fact that cow=dog :madr:

 

wheres the proof?








using calc, you can prove .999 = 1, but thinking outside that box... .999 != 1

its like saying 1 = 2 if you tilt your head and squint hard enough... or cow=dog h:

 

it is one of the homework questions, it doesnt show the proof, just the solution

im not sure where you are jumping from if .999... = 1 then 1=2

.999... is an infinite decimal
.999...9 would mean there is an actual end to it, thus a terminating decimal, thus it would not be equal to 1

if you cant see that 1/3 = .333... repeating then there is some other assumption you are making that isnt valid, repeating decimals are just as valid a number as an integer or a fraction, they arent approximations or rounding

edit - page 1.999... owned

 

i know 1/3 = .333... but .333r * 3 = 1., not .9999r

 

im gonna go watch tv now.

 

it sure does
.333... *3 = .999 r
think about when you learned to multiply and did it vertically

0.33333...
* 3
_______
0.00009...
+ .00090...
+ .00900...
+ .09000...
+ .90000...
________
0.99999...

there is no point at which you round up to get the 1
but we know that it does indeed equal 1

enjoy tv, im gonna go rub one out, all this math got me excited h:

 

You sir, are a hero among asians :hsugh: