For this one you have to know how the range is defined. Is this function defined for all real numbers? If so, then it is discontinuous when x >= -1. If y=0 when x>-1 then its discontinuous (there's a jump) @ x=-1.

Similarly, this would be discontinuous outside the range if you are dealing with real numbers. So whenever x<-1.

In all cases, if x was limited by the definition in the right way(say x could only take on values >-1) then the function in problem #2 could never be discontinuous.

Notice that @x=3, y=11 which is the same when x>3, this means there is no 'jump' or discontinuity at that point. i.e. the limit as you approach from the right is the same as the left.