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Old Jan 21, 2009 | 04:19 PM
  #21  
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Originally Posted by Red X
For this one you have to know how range is defined. Is this function defined for all real numbers? If so, then it is discontinuous when x >= -1.

Similarly, this would be discontinuous outside the range if you are dealing with real numbers. So whenever x<-1.

In all cases, if x was limited by the definition in the right way(say x could only take on values >-1) then the function in problem #2 could never be discontinuous.
What the fuck are you talking about?
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Old Jan 21, 2009 | 04:23 PM
  #22  
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Originally Posted by LT
What the fuck are you talking about?
A discontinuous function occurs when there is no y-value for a given x. So it matters how x is defined. Typically in a math textbook they'll say something like

x is an element in the set of real numbers.

This means that x can take on any real number value. Since the problems definition limited the y-values for a specific range of x-values and if the textbook says x can take on any real number value, then there is a range of x's that have discontinuous y-values. Namely for those that are not defined (when x<=-1). But it depends on the assumptions the book makes.

Last edited by Red X; Jan 21, 2009 at 04:26 PM.
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Old Jan 21, 2009 | 04:25 PM
  #23  
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If you explained this to me 7 years ago I'd say "A HA! YES OF COURSE!" However....now....brain cells aren't as populous as once before.
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Old Jan 21, 2009 | 09:25 PM
  #24  
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its a jackal
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Old Jan 21, 2009 | 10:07 PM
  #25  
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what is the point of that?
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Old Jan 21, 2009 | 10:24 PM
  #26  
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Originally Posted by Omie
its a jackal
Jackal?!!?
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Old Jan 21, 2009 | 10:35 PM
  #27  
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