No I'm not:fawk:

They paid $25=$8.33ea., the bell boy decided they needed a price gouge so he took $2, which now make's it $9ea. and they got $3 back.

ok my math is not challenged anymore

 

you're still confused. you're adding the $3 refund twice.
I hope you never become a cashier.

 

you're right, the pu55y has ruined my perfect thinkingh: I don't have your reserve

 

that's why I stay away from the pussy. It clouds your mind, and Mickey says it's bad for the knees.

 

I didn't add the refund twice, I said they got the $3 back so that make's up for the other $1 out of their $10, sorry I didn't write it all out, didn't think this was a legal and binding contract:fawk:

 

so, are we in aggreeance that they paid $9 exactly? I can never leave a confused student until he learns.

 

yes fawker

 

:yay: yay we win

 

heres my explaination

follow the numbers

3 people came in with 3 $10 bills
that makes it $30

the room cost $25
which means each paid <25/3= 8.33>

when they got their 1 dollar back...each in fact paid $9.33

9.33 x 3 = $28

the busboy got the remaining $2...

here's the trick...
they were suppose to pay $8.33 each...so each should get back $1.67 <10 - 8.33 = 1.67>

but the busboy only gave them back 1 dollar..
which makes them pay $9.00 compare to the real $8.33
all in all....
they each lost $.67

get it??

 

Everyone that quoted me and said I was wrong or whatever....

I heard this riddle when I was probably 10 years old, however it was asked incorrectly this time. The question is not supposed to be how much did each guy pay, the riddle is supposed to show the math and ask where the last dollar is.

I didn't post what I did because I was confused, I posted what I did to keep the riddle going, because some people replied "duh, they paid 9 dollars" without realising that it doesn't add up.

It just depends on how you think about it, some ways it adds up, some ways it doesn't.