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What am I doing wrong here?

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Old Mar 17, 2009 | 05:56 AM
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I am barely able to do these derivatives right now. I have no idea what that "ln" shit is though.
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Old Mar 17, 2009 | 06:03 AM
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42.



or asking HAN for an answer...
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Old Mar 17, 2009 | 08:29 AM
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dont they make graphing calculators to do this for us
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Old Mar 17, 2009 | 08:42 AM
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Originally Posted by F22B Prelude
y = ln(x^4+5x^2)^3/2

y' = ((1/x^4+5x^2)(4x^3+10x))^3/2

= 3/2(4x^3+10x/x^4+5x^2)
I cant tell you how much I enjoy not doing this stuff anymore.
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Old Mar 17, 2009 | 08:50 AM
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Oh I hated that with a passion.
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Old Mar 17, 2009 | 09:20 AM
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Calc 2 is where I ended my chances at being a Math Teacher.
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Old Mar 17, 2009 | 09:46 AM
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Originally Posted by F22B Prelude
y = ln(x^4+5x^2)^3/2

y' = ((1/x^4+5x^2)(4x^3+10x))^3/2

= 3/2(4x^3+10x/x^4+5x^2)
u forgot !, @, #, $, %, &, *, ♀, ♂, and \ö/
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Old Mar 17, 2009 | 09:48 AM
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Originally Posted by 95SiR
u forgot !, @, #, $, %, &, *, ♀, ♂, and ö/
i found this lol worthy... so lol
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Old Mar 17, 2009 | 09:48 AM
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Originally Posted by Draconius
Calc 2 is where I ended my chances at being a Math Teacher.
It's probably for the better...

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Old Mar 17, 2009 | 09:53 AM
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lol Studio Art - 0 hahahaha
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