say you have a password that is 12 characters long. these characters are both randomized letters a-z and numbers 0-9

how many combinations are there?

 

if there are no restrictions then

there are 10 numbers and 26 letters, therefore

36 possible combinations in each of the 12 spots so it is

36^12 combinations

this is if there is no distinguishability between capitalization and what not.

 

Nvm, I misread... not sure exactly
Edit: Oh, ok, it's 36! but only 12 times... so to the best of my knowledge, it's

36*35*34*33*32*31*30*29*28*27*26*25

EDIT::::: Ok, that's wrong too, because that would only work if you can't use the same letter/number again...so it's really 36^12 like he said... Holy crap that was bad.

 

cool, thanks kid who i don't don't name name to.

 

yeah its only 36!/(36-12)! if you cannot repeat digits letters.

 

what if you knew it was a combination of letters and numbers, it couldnt be just numbers or just letters

 

111111111111 > *

 

Total combinations - combos with just letters - combos with just numbers

36^12 - 26^12 - 10^12

 

thats what I answered