Thread: math question
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Old Oct 27, 2005 | 08:10 AM
  #3  
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MPerson
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Originally Posted by SolarWind
if there are no restrictions then

there are 10 numbers and 26 letters, therefore

36 possible combinations in each of the 12 spots so it is

36^12 combinations

this is if there is no distinguishability between capitalization and what not.
Nvm, I misread... not sure exactly
Edit: Oh, ok, it's 36! but only 12 times... so to the best of my knowledge, it's

36*35*34*33*32*31*30*29*28*27*26*25

EDIT::::: Ok, that's wrong too, because that would only work if you can't use the same letter/number again...so it's really 36^12 like he said... Holy crap that was bad.
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