then 4^4 i think is the possibilitys...
it is (4^4)/(4^13) chance

 

and allt his and i never even took stat, but i think i'm wrong on the possibilities

 

i'm gonna say 6, that sounds like a logical answer to me. no math involved, just 6.

 

the answer would be:
(13/52 * 39/51 * 38/50 * 37/49) + (39/52 * 13/51 * 38/50 * 37*49) + (39/52 * 38/51 * 13/50 * 37/49) + (39/52 * 38/51 * 37/50 * 13/49)

 

Yea, so it should be [(13/52) * (13/51) * (13/50) * (13/49)]

Since you are removing one card each time that is not a diamond. Edit: Shouldn't be averaged.

 

The answer was stated above.

(13/52) * (13/51) * (13/50) * (13/49)

 

[(4/13)/52]/4

thats it

 

well WHat is the correct answer? we have like 15 possible answers out there

 

pretend you take all the diamonds out. you have 39 cards. form all the possible combinations possible. there are 39!/36!/3! total possibilities.

to each of those possibilities, you can add 1 diamond and form the hand you are looking for. there are 13 diamonds.

so take 13 and multiply it by 39!/36!/3!. that is your total combinations of 1 diamond out of 4 cards.

as for total possible 4 card hands, the combinations is 52!/48!/4!

now you have 16 answers. =)

 

wait, but [(13/52) * (13/51) * (13/50) * (13/49)] = .25*.254*.26*.265 = .0043 something... i would expect the answer to be closer to 100%? (sorry i'm not good at math, especially statistics)

i appreciate the help though guys...