Originally Posted by
Red X
dude, I whipped something up real quick. You can simplify this:
Like I see a 2 that can be factored out etc.
oh holy fuck dont do it that way
y=ln(x^4 + 5x^2)^(3/2)
use ln manip. to get
y=(3/2)(ln(x^4 + 5x^2)
then use the def of deriv of ln to get
y'=(3/2) [(1/(x^4 + 5x^2))(4x^3 + 10x)]
simplify
y'=(12x^3 + 30x)/(2x^4 + 10x^2)
basically y=ln(x)
y'=(dx/x)
but only for lower level stuff, dont do this in 253 or above