Whered the x squared go....

 

homey. You can't possibly be this bad... I gave you two separate posts showing you how it goes. I showed you the general rule AND I gave you the answer to your specific problem. I have no idea what else to do.

 

Oh, you took the x squared out and made it into a chain rule problem....I'm trying to solve it using the quotient rule or product rule...thanks for the help though

 

No, I used the product rule.

Actually it IS the product rule, not chain rule.

 

Still doesn't make any damn sense

 

can you solve the derivative for x^2?


Do the same process but now do it for x^(-2)

 

its just a specific case of the chain rule, but i guess it gets its own name these days

 

whats the issue with the quotient rule i did?
caught up somewhere?


do you understand log and ln ok?

can you do other derivs like y=(x-2)/(3x^2+4x) with the quotient rule?

 

I got it now

I know the rules u'v + uv' = product and u'v - uv'/v2 = quotient

I was confused with (2) (ln) and then multiply that by (x^-2) i was thinking like (u)(v)(x) or some shit...but I got it figured out now..

You just keep (2ln(x+3) as U and (x^-2) as V...... then do the product rule

 

nice