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Calculus question

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Old Mar 6, 2009 | 06:16 AM
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Default Calculus question

Can someone please explain to me how the first derivative of x²(72-4x) is 12x(12-x). I am not sure how to get that answer.
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Old Mar 6, 2009 | 06:21 AM
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shit pete... been a while since i've done any math. tried solving it and came out with something really different.
no clue
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Old Mar 6, 2009 | 06:23 AM
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Originally Posted by Pete
Can someone please explain to me how the first derivative of x²(72-4x) is 12x(12-x). I am not sure how to get that answer.
take the derivative of the individual pieces.

dy/dx(72x^2 - 4x^3)= dy/dx(72x^2)-dy/dx(4x^3)

=144x - 12x^2 => 12x(12-x)

If you don't want to open up the parenthesis then you can use the rule:

f*g' + g*f' = (fg)'

so:

f= x^2, f'=2x
g=72-4x, g'=-4

you get:

x^2*(-4)+(72-4x)(2x) = 12x(12-x)

Last edited by Red X; Mar 6, 2009 at 06:30 AM.
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Old Mar 6, 2009 | 06:35 AM
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You have to be kidding ^
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Old Mar 6, 2009 | 06:37 AM
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Originally Posted by Red X
take the derivative of the individual pieces.

dy/dx(72x^2 - 4x^3)= dy/dx(72x^2)-dy/dx(4x^3)

=144x - 12x^2 => 12x(12-x)

If you don't want to open up the parenthesis then you can use the rule:

f*g' + g*f' = (fg)'

so:

f= x^2, f'=2x
g=72-4x, g'=-4

you get:

x^2*(-4)+(72-4x)(2x) = 12x(12-x)
Originally Posted by CRAIGHIMSELF
You have to be kidding ^

Funny how this makes sense to me
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Old Mar 6, 2009 | 06:38 AM
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Originally Posted by RicoD
Funny how this makes sense to me
you like math too
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Old Mar 6, 2009 | 06:41 AM
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Originally Posted by Red X
you like math too

its all addition and subtraction in different forms h:
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Old Mar 6, 2009 | 06:50 AM
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wow, I am surprised I still remembered how to do this.
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Old Mar 6, 2009 | 06:51 AM
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that was actually a really good explanation. i remember it now
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Old Mar 6, 2009 | 07:05 AM
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Originally Posted by Red X
take the derivative of the individual pieces.

dy/dx(72x^2 - 4x^3)= dy/dx(72x^2)-dy/dx(4x^3)

=144x - 12x^2 => 12x(12-x)

If you don't want to open up the parenthesis then you can use the rule:

f*g' + g*f' = (fg)'

so:

f= x^2, f'=2x
g=72-4x, g'=-4

you get:

x^2*(-4)+(72-4x)(2x) = 12x(12-x)

Im so glad I went through this in college and dont have to do it again!
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