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math doods

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Old Jan 25, 2005 | 03:41 PM
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Default math doods
how do i solve for a the sides of a triangle when i have 1 angle and 2 sides without a right angle
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Old Jan 25, 2005 | 03:42 PM
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law of cosines

c^2 = a^2 + b^2 - 2ab cos(theta)
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Old Jan 25, 2005 | 03:43 PM
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do the cosine or sine or tangent to solve.
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Old Jan 25, 2005 | 03:45 PM
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Originally Posted by SOLDIER [X]
do the cosine or sine or tangent to solve.
just to clear you up you nee a 90* angle to do those directly... thanks jani
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