Originally Posted by Pete
The IP address 172.16.213.16/20 is a host address in which of the following subnets:
A) 172.16.213.224
B) 172.16.213.240
C) 172.16.0.0
D) 172.16.208.0
E) 172.16.176.0
All I can figure out is that the subnet mask is 255.255.240.0 and that there are 12 bits reserved for hosts (I think). Can someone help me out? Thanks.
14 bits reserved for hosts
1 network bit
1 broadcast
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