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Math Whiz's
My friend asked if anyone can help him on this lil thingamabob:
a cylinder 60 cm high has a circumference of 20 cm. A string makes exactly 4 complete turns around the cylinder while its two ends touch the cylinder's top and bottom, like a barber's pole. how long is the string in cm? |
~132.7 cm
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Found out it's my friend's cousin, for his prjoect or something. We told him to go to home depot and freakin' buy a 60 CM high cylinder with a 20 cm circumference and wrap a string see how long.
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Originally Posted by MaxBoosT
Found out it's my friend's cousin, for his prjoect or something. We told him to go to home depot and freakin' buy a 60 CM high cylinder with a 20 cm circumference and wrap a string see how long.
length = 60 cm width of top and bottom = (Pi x diameter = 20) = 20/3.14159... = 6.366 cm 60 + 60 + 6.366 + 6.366 = 132.732 = ~132.7 cm |
i say the answer is 100. pythagorean might come in handy *hint hint*
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Interesting.
I didn't even attempt this, I already have a headache. Good sh*t RB :bigok: |
Originally Posted by jclau00
i say the answer is 100. pythagorean might come in handy *hint hint*
"Unroll" the cylinder, and you will get four triangles. The hypotenuse of each one of these is 25 cm, so the total length is 100 cm. |
ohhh, I read it wrong. I thought they meant wrap it up and down vertically :doh:
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